Let the number be represented by x. When x is divided by 3, the remainder is 2, which can be expressed as x ≡ 2 (mod 3). Similarly, when x is divided by 7, the remainder is also 2, which can be written as x ≡ 2 (mod 7). To find the number that satisfies both conditions, we can use the Chinese Remainder Theorem to find the smallest positive integer that satisfies both congruences, which in this case would be 23.
It is an integer which, when divided by 2, leaves a remainder of 1.
Do you mean what, when divided by 2, leaves a remainder? That'd be any odd number (or fraction).
It is 997.
2
The largest 2-digit number is 99. When 99 is divided by 4, the quotient is 24 with a remainder of 3. This is because 99 divided by 4 equals 24 with a remainder of 3.
It is an integer which, when divided by 2, leaves a remainder of 1.
3
26
It is a number which, when divided by 2, leaves no remainder.
It is any number which, when divided by 2, leaves no remainder.
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
Do you mean what, when divided by 2, leaves a remainder? That'd be any odd number (or fraction).
It is a number which leaves no remainder when divided by 2.
If it leaves no remainder when divided by 2 then it is an even number.
85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11
Because it leaves a remainder of 1 when divided by 2.
Because when it is divided by 2, it leaves a remainder of 1.