Let the number be represented by x. When x is divided by 3, the remainder is 2, which can be expressed as x ≡ 2 (mod 3). Similarly, when x is divided by 7, the remainder is also 2, which can be written as x ≡ 2 (mod 7). To find the number that satisfies both conditions, we can use the Chinese Remainder Theorem to find the smallest positive integer that satisfies both congruences, which in this case would be 23.
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Well, honey, if a number leaves a remainder of 2 when divided by 3 and 7, it means it's 2 more than a multiple of both 3 and 7. So, the number is actually 23, because 21 is the smallest number that is a multiple of both 3 and 7, and adding 2 to that gives you 23. Math can be sassy too, you know!
Oh, dude, you're hitting me with some math vibes! So, if a number leaves a remainder of 2 when divided by 3 and 7, it means the number is 2 more than a multiple of both 3 and 7. So, the number could be 23, 44, 65, or any number that fits that pattern. Math can be a trip, right?
It is an integer which, when divided by 2, leaves a remainder of 1.
Do you mean what, when divided by 2, leaves a remainder? That'd be any odd number (or fraction).
It is 997.
2
2521