18 and 36 do. So do 18 and 54, 36 and 54, 18 and 72, 54 and 72, and an infinite number of other pairs of numbers.
The two numbers are 18 and 36. Let the two numbers be x and y, then: x ÷ y = 2 ⇒ x = 2y x + y = 54 ⇒ 2y + y = 54 ⇒ 3y = 54 ⇒ y = 18 ⇒ x = 2y = 2 x 18 = 36
No. 54 is only evenly divisible by these numbers: 1, 2, 3, 6, 9, 18, 27, 54.
You can divide 54 by these numbers: 1, 2, 3, 6, 9, 18, 27, 54.
The numbers that go into both 18 and 54 evenly are 1, 2, 3, 6, 9, 18.
1 2 3 6 9 18 27 and 54.
1, 2, 3, 6, 9, 18, 27, 54.
18 and 9 * * * * * Not so. LCM(9, 18) = 18, not 54. The correct answer is 18, 27.
17 + 18 + 19 = 54 12 + 13 + 14 + 15 = 54 2 + 3 + 4 + ... + 10 = 54
6, 2, ⅔
54/2=27, 27/3=9, 9/3=3. 1x2x3x3x3=54 If a number can be expressed as a product of two whole numbers, then the whole numbers are called factors of that number. 54 = 1 x 54 = 2 x 27 = 3 x 18 = 6 x 9 Therefore, the factors of 54 are 1, 2, 3, 6, 9, 18, 27 and 54
To find this, you first have to split the numbers into their prime factors: 18 = 2x3x3 54 = 2x3x3x3 The next step is to identify any common prime factors. In this case both numbers have a 2 and two 3s as prime factors. Multiply these together gives you: 2x3x3 = 18 Therefore the HCF of 18 and 54 is 18.
54/2=27 27/3=9 9/3=3 54= 2*3*3*3 so the following numbers go into 54 2, 3, 6, 9, 18, 27
Factors are the numbers you multiple together to get another number. 54: 1, 2, 3, 6, 9, 18, 27, 54 54 has 8 factors.
1, 2, 3, 6, 9, 18, 27, 54.
4, 54, 8, 27, 12, 18, 2, 6 & 36
The two numbers 18 and 27. Factorising the lcm and gcf gives: 54 = 2 × 3³ 9 = 3² There must be 3² in both numbers, but there must be a 3³ and a 2 which must appear in the prime factorisations of the two numbers. Putting a 2 with one 3² and a 3 with the other 3² leads to the two numbers: 2 × 3² = 18 3 × 3³ = 3³ = 27 as the two smallest numbers with gcf=9 and lcm=54. The other distribution of both 2 and 3 with one 3² results in the two number 3² = 9 and 2 × 3³ = 54, the latter of which is larger than both the 18 and 27 previously found.