2(x + y) = 156
x = 2y
Here x = length of rectangle and y = width
y=4x
perimeter = pi * diameter, or 2 * pi * radius
It works out as 19 m in length and 13 m in width.
in helmholtz vector equation why F=-∆ф+∆xA?
12r = p
By halving its perimeter and using the quadratic equation formula.
y=4x
perimeter = pi * diameter, or 2 * pi * radius
It works out as 19 m in length and 13 m in width.
Assuming the object is a rectangular parallelepiped, use its density to find its volume and solve the equation V abc for c where a, b, and c are the height, length and width respectively
in helmholtz vector equation why F=-∆ф+∆xA?
Circumference ("perimeter") of a circle = (pi) x (diameter of the circle)
12r = p
The perimeter of a plane figure is the length of its boundary. Thus the perimeter of a rectangle of length L and width W is 2L + 2W. The perimeter of a circle is the length of its circumference.
S1+s2+s3
You need to write two equations with two variables each, for the two facts. Remembering that the perimeter is the sum of the lengths of all the sides:Write an equation for the perimeter of the original rectangle:perimeter = 2(length + width)26 = 2(l+w) (equation 1)Write an equation for the area of the increased rectangle:A = length x widthA = (l+4)(w+3) (equation 2)Solve the two equations simultaneously; and you'll get the width and length of the original rectangle.
It depends on the shape, but I'm assuming you mean a square or rectangle. If it is not this shape, edit the question. In this equation L=Length W=Width So, to get the perimeter, you would use this equation: 2L+2W= Perimeter