You shoulda done your homework.
The dimensions are 7 by 12 meters Check: perimeter = 2*(7+12) = 38 meters and area = 7*12 = 84 square meters
To find the dimensions of the largest rectangular pen that can be enclosed with 64 meters of fence, we can use the formula for the perimeter of a rectangle, which is (P = 2(l + w)), where (l) is length and (w) is width. Setting the perimeter equal to 64 meters gives us (l + w = 32). To maximize the area (A = l \times w), we can express (w) as (w = 32 - l) and find the maximum area occurs when (l = w = 16). Therefore, the dimensions of the largest rectangular pen are 16 meters by 16 meters, making it a square.
To find the dimensions of a parking lot with an area of 918 square meters and a perimeter of 122 meters, we can set the length as ( l ) and the width as ( w ). The equations are ( lw = 918 ) and ( 2(l + w) = 122 ). Solving these equations simultaneously, we find that the dimensions are approximately 39 meters in length and 23.5 meters in width.
To find the perimeter, we first need to determine the shape of the area. If we assume it's a square with an area of 64 square meters, the length of each side would be the square root of 64, which is 8 meters. The perimeter of a square is calculated as 4 times the length of one side, so the perimeter would be 4 × 8 = 32 meters. If the shape is different, the perimeter would need to be calculated based on its specific dimensions.
The perimeter will be tripled.
The dimensions are 7 by 12 meters Check: perimeter = 2*(7+12) = 38 meters and area = 7*12 = 84 square meters
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
To find the dimensions of the largest rectangular pen that can be enclosed with 64 meters of fence, we can use the formula for the perimeter of a rectangle, which is (P = 2(l + w)), where (l) is length and (w) is width. Setting the perimeter equal to 64 meters gives us (l + w = 32). To maximize the area (A = l \times w), we can express (w) as (w = 32 - l) and find the maximum area occurs when (l = w = 16). Therefore, the dimensions of the largest rectangular pen are 16 meters by 16 meters, making it a square.
To calculate the perimeter of seven acres, we first need to convert acres to square meters. One acre is equal to 4046.86 square meters, so seven acres would be 28328.02 square meters. The perimeter of a rectangle (assuming the seven acres form a rectangular shape) is calculated by adding all four sides. Without knowing the exact dimensions of the seven acres, we cannot determine the exact linear meters of the perimeter.
18 and 8
16 √5 meters
To find the dimensions of a parking lot with an area of 918 square meters and a perimeter of 122 meters, we can set the length as ( l ) and the width as ( w ). The equations are ( lw = 918 ) and ( 2(l + w) = 122 ). Solving these equations simultaneously, we find that the dimensions are approximately 39 meters in length and 23.5 meters in width.
To find the perimeter, we first need to determine the shape of the area. If we assume it's a square with an area of 64 square meters, the length of each side would be the square root of 64, which is 8 meters. The perimeter of a square is calculated as 4 times the length of one side, so the perimeter would be 4 × 8 = 32 meters. If the shape is different, the perimeter would need to be calculated based on its specific dimensions.
A ziggurat could be oval, rectangular, square, or any other shape. If happened to have a square base, its perimeter would be four times its length (4 x 22 meters = 88 it meters).
Divide by 100: 43cm / 100 = 0.43 meters.
If each side of a square is 7.5 meters then its perimeter is 30 meters
The perimeter of this square is 56.569 meters.