Q: The reciprocal of an integer plus the reciprocal of two times the integer plus two equals 2 over 3 Find the integer?

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80

2/x =16/20 16x = 40 x = 2.5

Put a 1 over it. The reciprocal of 3 is 1/3

10

To find out how many times 11 goes into 616, you would perform integer division. 616 divided by 11 equals 56 with a remainder of 0. Therefore, 11 goes into 616 exactly 56 times.

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2

80

4

This question can be expressed algebraically as: (1/n) + (1/(2n)) + 2 = 23, (1/n) + (1/(2n)) =21, ((1+2)/(2n)) = 21, (3/(2n)) = 21, or 2n = (3/21), 2n = (1/7), so n = (1/14). This, by the way, is an elementary algebraic proof that the solution to the above relation is (1/14). Anyway, to answer the question, reread the question: "[What integer is such that] the reciprocal of the integer...". notice, the reciprocal of (1/14) is 14, which is the integer in question! ^_^

2/x =16/20 16x = 40 x = 2.5

1/x + 1/2x + 2 = 2/3; 3/2x = -4/3; -8x = 9 (2 + 1)/2x + 2 = 2/3 3 + 4x = 4x/3 9 + 12x = 4x 8x = -9 x = -1 1/8 which isn't an integer but fits the stated conditions If you're doing A+ the answer is 2.

The reciprocal of a number plus the reciprocal of twice the number equals Find the number. 1/2 find the number

Put a 1 over it. The reciprocal of 3 is 1/3

-3

-3

10

Let the number be n. We have: 3 x 1/n = 9 x 1/6 (simplify) 3 x 1/n = 3 x 1/2, this is true only for n = 2.