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When dividing 13 by 10, 1 is the quotient and 3 is the remainder
16.6154
Nope - it results in a remainder after being divided 11 times.
If the question means what is 54 in binary then this can be solved by continually dividing by 2 and noting the remainder. 54 ÷ 2 = 27 remainder 0 27 ÷ 2 = 13 remainder 1 13 ÷ 2 = 6 remainder 1 6 ÷ 2 = 3 remainder 0 3 ÷ 2 = 1 remainder 1 1 ÷ 2, final remainder 1 Reading the remainder values from bottom to top gives 110110 which is the binary equivalent of 54.
They very definitely are not! You cannot have a remainder that is larger than the divisor. Furthermore, division by 6 cannot leave a remainder of 12 since 12 is divisible by 6!
13.5
3.25
34.6842
0.0131
Plus Two Results of Kerala will be published on 13 may
13 remainder 5
1276710 = ?Dividing by 163 (4096), we have 3 r 479.3(163)Dividing by 162 (256), we have 1 r 223.1(162)Dividing by 16, we have 13 r 15.d(16)Now, 15 is the final remainder, which yields f for the end digit.Thus:31df is your answer.