as logically as i can solve it, here is the solution x + 3x + 60 = 180 4x + 60 = 180 4x = 180 - 60 4x = 120 4x/4 = 120/4 x = 30 thus angle 1 = 30 degrees, angle 2 = 60 degrees, and angle 3 = 90 degrees hope this helps. in my equation, the x is angle 1 and the 3x (because it is three times as large as angle 1) is angle 3, and the 60 is angle 2. all angles in a triangle must total 180 degrees, so this equation is legitimate, and the solution is correct.
The third angle is (128 degrees) minus (the second angle).
It is 90-28 = 62 degrees
Let's assume the measure of the first angle is x degrees. The second angle is one-third as large as the first, so its measure is (1/3) * x = x/3 degrees. The third angle is two-thirds as large as the first, so its measure is (2/3) * x = 2x/3 degrees. Therefore, the measures of the angles in the triangle are x degrees, x/3 degrees, and 2x/3 degrees.
It will be 62 degrees because 90-28 = 62
The angles are: 43 degrees. 38 degrees and 99 degrees which all add up to 180 degrees
The third angle is (128 degrees) minus (the second angle).
It is 90-28 = 62 degrees
54 degrees
The sum of the measures of the angles of a triangle is 180 degrees. First, calculate the sum of the two known angles. Then subtract that result from 180. That difference is the measure of the third unknown angle. Given: One angle of a triangle is 15 degrees and the second angle of the triangle is 85 degrees. To find: We need to find the third angle of the triangle. Let the third angle of the triangle be x. We know that the sum of the angles in a triangle is 180 degrees. ==> 15 degrees + 85 degrees + x degrees = 180 degrees. ==> 100 degrees + x degrees = 180 degress. ==> x = 180 degrees - 100 degrees. ==> x = 80 degress. Therefore the third angle of the triangle is 80 degrees.
In a triangle the measure of the first angle is four times the measure of the second angle. The measure of the third angle is 18 degrees more than the second angle. What is the measure of the first angle? 68 43 17 95
100.
Let the measure of the first angle be x⁰. So that the second angle would be (x + 21)⁰, and the third one would be (x - 15)⁰.Since the sum of angle measures in a triangle is 180⁰ we have:x + x + 21 + x - 15 = 1803x = 174x = 58Thus, the first angle is 58⁰, the second angle is 79⁰, and the third angle is 43⁰.
If its a right angle triangle then the second acute angle is 62 degrees
Let's assume the measure of the first angle is x degrees. The second angle is one-third as large as the first, so its measure is (1/3) * x = x/3 degrees. The third angle is two-thirds as large as the first, so its measure is (2/3) * x = 2x/3 degrees. Therefore, the measures of the angles in the triangle are x degrees, x/3 degrees, and 2x/3 degrees.
Let the second angle of the triangle be A. Then angle 1 = 2A : and angle 3 = 3A - 12 The internal angles of a triangle total 180° therefore :- 2A + A + (3A - 12) = 180 6A - 12 = 180 : 6A = 192 : A = 32 The angles measure 64° , 32° and 84° .
It will be 62 degrees because 90-28 = 62
Let x equal the first angle.let 4x= the second anglelet 3x+10x+4x+3x+10=180 The sum of the interior angle measures of a triangle is 180 degrees.8x+10=180 combine like terms8x=170 addition(subtraction) property of equalityx=21.25 degrees