restated this question using angles a,b,c:
b=4a
c=a+b+40
a+b+c=180 (since all triangles are 180 degrees)
find b
c=a+4a+40
c=5a+40
a+4a+(5a+40)=180
10a=140
a=14
b=4(14)=56 (answer to your question)
c=14+56+40=110
The angles are: 43 degrees. 38 degrees and 99 degrees which all add up to 180 degrees
Let's assume the measure of the first angle is x degrees. The second angle is one-third as large as the first, so its measure is (1/3) * x = x/3 degrees. The third angle is two-thirds as large as the first, so its measure is (2/3) * x = 2x/3 degrees. Therefore, the measures of the angles in the triangle are x degrees, x/3 degrees, and 2x/3 degrees.
The third angle is (128 degrees) minus (the second angle).
It is 90-28 = 62 degrees
It will be 62 degrees because 90-28 = 62
The angles are 40, 80 and 60 degrees.
The sum of the measures of the angles of a triangle is 180 degrees. First, calculate the sum of the two known angles. Then subtract that result from 180. That difference is the measure of the third unknown angle. Given: One angle of a triangle is 15 degrees and the second angle of the triangle is 85 degrees. To find: We need to find the third angle of the triangle. Let the third angle of the triangle be x. We know that the sum of the angles in a triangle is 180 degrees. ==> 15 degrees + 85 degrees + x degrees = 180 degrees. ==> 100 degrees + x degrees = 180 degress. ==> x = 180 degrees - 100 degrees. ==> x = 80 degress. Therefore the third angle of the triangle is 80 degrees.
Let the second angle be x degrees. The first angle would then be x + 24 degrees, and the third angle would be 4x degrees. According to the triangle angle sum theorem, the sum of all three angles in a triangle is 180 degrees. Therefore, you can set up the equation x + (x + 24) + 4x = 180 and solve for x to find the measures of all three angles.
The angles are: 43 degrees. 38 degrees and 99 degrees which all add up to 180 degrees
Let's assume the measure of the first angle is x degrees. The second angle is one-third as large as the first, so its measure is (1/3) * x = x/3 degrees. The third angle is two-thirds as large as the first, so its measure is (2/3) * x = 2x/3 degrees. Therefore, the measures of the angles in the triangle are x degrees, x/3 degrees, and 2x/3 degrees.
If two angles are supplementary, and one angle measures 30 degrees, then the second angle must measure 150 degrees. This is because by definition if two angles are supplementary, then they must up to 180 degrees.
41
100.
If its a right angle triangle then the second acute angle is 62 degrees
If two angles are complementary, then they equal 90 degrees. If one angle is 62 degrees we subtract it from 90 and get 38 degrees.
Angle 1 = 30 degrees Angle 2 = 50 degrees Angle 3 = 100 degrees.
The third angle is (128 degrees) minus (the second angle).