Want this question answered?
Yes, it is.
You take each equation individually and then, on a graph, show all the points whose coordinates satisfy the equation. The solution to the system of equations (if one exists) consists of the intersection of all the sets of points for each single equation.
It can comprise all the points of a curve (including a line) in 2-dimensional space. There are only a few, exceptional, cases when one equation in two variables will give a single point as a solution.
Is equidistant from all points on the circle.
The center of the circle.
The solution set is all points on the circle.
Yes, it is.
The solution set for a given equation is the set of all points such that their coordinates satisfy the equation.
A solution point, in R2, is an ordered pair that satisfies the function.e.g. given the function, f(x) = x2, a solution point is (0,0), or (2,4), etc.The set of all solution points of an equation is equivalent to the graph of an equation.
the answer is false - apex
The solution of a linear equation in two variable comprises the coordinates of all points on the straight line represented by the equation.
solution
We identify a set of points in the relevant space which are part of the solution set of the equation or inequality. The space may have any number of dimensions, the solution set may be contiguous or in discrete "blobs".
You take each equation individually and then, on a graph, show all the points whose coordinates satisfy the equation. The solution to the system of equations (if one exists) consists of the intersection of all the sets of points for each single equation.
To graph the set of all the solutions to an equation in two variables, means to draw a curve on a plane, such that each solution to the equation is a point on the curve, and each point on the curve is a solution to the equation. The simplest curve is a straight line.
This is the center of the circle. From the center of the circle, all the points on the circle are equally distant.
all the points in the inscribed circle are also in the bigger circle. If all the points in the outside circle are the set O ... and all the points in the inner circle are the set I... Then I is a subset of O, just like a venn diagram