No. The square root of any number between 0 and 1 is bigger than itself. For example, sqrt(1/4) = 1/2 or sqrt(1/9) = 1/3. The square roots of 0 and 1 are the same as the number itself. The square root of any number x that is bigger than 1 is less than x.
You eventually get the answer 1
No, not always since: if a number is more than 1, then its square root is smaller than the number. if a number is less than 1, then its square root is bigger than the number.
139, the square root of 19321 is less than 140.
* == == what are the values of square root of x is less than 7 ? ----
only if x is greater than 1
You eventually get the answer 1
Yes, as for example the square root of 2 is a positive irrational number.
No, not always since: if a number is more than 1, then its square root is smaller than the number. if a number is less than 1, then its square root is bigger than the number.
139, the square root of 19321 is less than 140.
the square root of 3, the square root of 5, the square root of 6, the square root of 7, the square root of 8 etc
No. The square roots of numbers between 0 and 1 (not including 0) are greater than or equal to (in the case of 1) the number. The square root of 0.49 is 0.7 for example.
The square root of 1597.44 is about 0.032 less than 40, the square root of 1600.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
7.937253933slightly less than 8 (square root of 64 is 8)
* == == what are the values of square root of x is less than 7 ? ----
only if x is greater than 1
The square root of a number below 36 can vary depending on the specific number. For example, the square root of 25 is 5, while the square root of 9 is 3. However, the square root of any number below 36 will always be less than 6, since 6 is the square root of 36. Thus, it is crucial to specify the number in question to determine its square root accurately.