Call the numbers: x, (x+1), and (x+2)
The sum is: x + (x+1) + (x+2) = 3x + 3 = 207
3x = 204
x = 68
The numbers are 68, 69, and 70.
207
They are: 68+69+70 = 20768, 69 and 70.
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11
The average is 207.To work it out, add all the numbersand divide it by how many numbers there are.In this case, (236+178)/2=207
You need at least two numbers to find a GCF. The prime factorization of 207 is 3 x 3 x 23.
The three numbers are 205, 207 and 209.
207
They are: 68+69+70 = 20768, 69 and 70.
Let the integers by 'm' & 'm+1'. Consecutive. Hence m + m + 1 = 207 2m + 1 = 207 2m = 206 m = 103 Hence m + 1 = 104 So the two consecutive integers are 103, & 104.
You need at least two numbers to find a GCF.
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11
The average is 207.To work it out, add all the numbersand divide it by how many numbers there are.In this case, (236+178)/2=207
You need at least two numbers to find a GCF. The prime factorization of 207 is 3 x 3 x 23.
The integers are 67, 69 and 71.
1, 3, 9, 23, 69, 207.
To find two consecutive 2-digit numbers that multiply to 812, we can set up the equation ( x(x+1) = 812 ), where x represents the first number. By solving this quadratic equation, we find that the two consecutive numbers are 28 and 29. This is because 28 * 29 = 812.
Factors are numbers you can multiply together to get another number. 207: 1, 3, 9, 23, 69, 207