Call the numbers: x, (x+1), and (x+2)
The sum is: x + (x+1) + (x+2) = 3x + 3 = 207
3x = 204
x = 68
The numbers are 68, 69, and 70.
207
They are: 68+69+70 = 20768, 69 and 70.
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11
You need at least two numbers to find a GCF. The prime factorization of 207 is 3 x 3 x 23.
The average is 207.To work it out, add all the numbersand divide it by how many numbers there are.In this case, (236+178)/2=207
The three numbers are 205, 207 and 209.
207
They are: 68+69+70 = 20768, 69 and 70.
You don't say whether they've to be added or multiplied! 103 + 104 = 207; 207 = 3 x 3 x 23 so there is no solution in integers.
You need at least two numbers to find a GCF.
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11
The average is 207.To work it out, add all the numbersand divide it by how many numbers there are.In this case, (236+178)/2=207
You need at least two numbers to find a GCF. The prime factorization of 207 is 3 x 3 x 23.
The integers are 67, 69 and 71.
To find two consecutive 2-digit numbers that multiply to 812, we can set up the equation ( x(x+1) = 812 ), where x represents the first number. By solving this quadratic equation, we find that the two consecutive numbers are 28 and 29. This is because 28 * 29 = 812.
1, 3, 9, 23, 69, 207.
45