To solve this problem:
x+(x+1)+(x+2)+(x+3) = -2
x+x+x+x +1+2+3 = -2
4x+6 =-2
4x+6-6 = -2 -6
4x= -8
x=-2
Therefore, the numbers are -2, -1, 0, and 1.
(x) + (x+1) + (x+2) + (x+3) = -2
4x + 6 = -2
4x = -8
x = -2
They are -2, -1, 0, and 1 .
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
The integers are -2, 0, 2 and 4.
The numbers are -4, -2, 0, and 2.
If n is the smallest of the four integers, their sum is 4n+6.
-2, -4, -6
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
The integers are -2, 0, 2 and 4.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
The integers are -2, -1, 0 and 1.
The numbers are -4, -2, 0, and 2.
-4 and -5
If n is the smallest of the four integers, their sum is 4n+6.
They are -6, -4 and -2.
-2, -4, -6
The integers are -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5. The largest is five.
Since 16 + 25=41, we know the integers are 4 and 5.
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