To solve this problem:
x+(x+1)+(x+2)+(x+3) = -2
x+x+x+x +1+2+3 = -2
4x+6 =-2
4x+6-6 = -2 -6
4x= -8
x=-2
Therefore, the numbers are -2, -1, 0, and 1.
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(x) + (x+1) + (x+2) + (x+3) = -2
4x + 6 = -2
4x = -8
x = -2
They are -2, -1, 0, and 1 .
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
The integers are -2, 0, 2 and 4.
The numbers are -4, -2, 0, and 2.
If n is the smallest of the four integers, their sum is 4n+6.
-2, -4, -6