This is impossible with positive integers. However, four numbers separated by a difference of 1 with a sum of -92 are:
-21.5
-22.5
-23.5
-24.5
9 and 11 92 = 81 112 = 121 81+121 = 202
The closest you can get is 90, which is 28+30+32, unless you can repeat the integers, then it will be 30+30+32. Since 92/3 = 30.666, this question cannot have an answer within the parametres set.
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
The two integers between 92 are 93 and 94. Integers are whole numbers, and these two numbers come directly after 92 in the number line.
The square root of 92 lies between the integers 9 and 10. This is because (9^2 = 81) and (10^2 = 100), so (9 < \sqrt{92} < 10). Therefore, the two integers that the square root of 92 lies on are 9 and 10.
The integers are -92, -91, -90 and -89.
They are 92 and 93.
They are: 92+93+94+95 = 374
112+92 is 202.
They are: 90+91+92 = 273
9 and 11 92 = 81 112 = 121 81+121 = 202
The numbers are 20, 22, 24 and 26.
The closest you can get is 90, which is 28+30+32, unless you can repeat the integers, then it will be 30+30+32. Since 92/3 = 30.666, this question cannot have an answer within the parametres set.
x + x + 1 + x + 2 = 279 3x + 3 = 279 3x = 279 - 3 = 276 x = 92 Hence the three consecutive numbers are 92, 93, and 94
There are two consecutive even integers: 90 and 92.
The square root of 92 will be +/- 9.59. It lies between the consecutive integers of 9 and 10.
No four consecutive whole numbers have a sum of 360. 88 + 89 + 90 + 91 = 358 . . . too small 89 + 90 + 91 + 92 = 362 . . . too big