The sum of an odd and even number is always odd because there's always one left over. Think of any odd number as being any even number plus one. If you add two even numbers, the answer is always even. If you add an even and an odd (plus one), the answer is always odd.
It is always an odd number
Yes. One has to be the square of an odd number. The other square has to the the square of the even number either before or after the odd number. If this is confusing just plug in real values. In either case, an odd times and odd is odd. Therefore one of the squares has to be odd. AN even times an even, however, is always even. Therefore, the second square has to be even. Thus, one of the squares is even and the other is odd. An even plus and odd is always odd.
It's just one of those laws of maths. It can be used as an indication to whether the answer could be right. It's similar to even + even = even Even + odd = odd Odd + odd = even
It never comes out even. There is always one left over when you an odd number by two.
The sum of an odd and even number is always odd because there's always one left over. Think of any odd number as being any even number plus one. If you add two even numbers, the answer is always even. If you add an even and an odd (plus one), the answer is always odd.
The sum of an odd and even number is always odd because there's always one left over. Think of any odd number as being any even number plus one. If you add two even numbers, the answer is always even. If you add an even and an odd (plus one), the answer is always odd.
The sum of an odd and even number is always odd because there's always one left over. Think of any odd number as being any even number plus one. If you add two even numbers, the answer is always even. If you add an even and an odd (plus one), the answer is always odd.
It is always an odd number
The 4 is even. The 5 is odd. Their sum, 9, is odd. The sum of (one even number) + (one odd number) is always odd.
Yes. One has to be the square of an odd number. The other square has to the the square of the even number either before or after the odd number. If this is confusing just plug in real values. In either case, an odd times and odd is odd. Therefore one of the squares has to be odd. AN even times an even, however, is always even. Therefore, the second square has to be even. Thus, one of the squares is even and the other is odd. An even plus and odd is always odd.
They never do. Odds and evens alternate. Let x equal any number, even or odd. x + 1 will always be the other kind. The sum, 2x + 1, will always be odd, since 2x is always even and one more than an even is always odd.
Square of any even counting number is always an even number and square of any odd number is always odd. Addition of even number and its square is always an even number because even + even results in even number and addition of odd number and its square is always an even number because odd + odd = even number. Since natural or counting numbers consists of only even and odd, which comes one by one after each other. So, according to the question and the given condition only one answer comes out which is an even number. e.g. let us take the counting number like 8, square of 8 = 82 =64 and addition of 8 and its square =8+64 =72 which is an even number.
No two consecutive numbers have a product that is an even number. Any two consecutive numbers include one odd number and one even number. The product of one odd number and one even number is always an odd number.
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.
One always gets an even number.
This answer cannot be answered because two consecutive numbers consist of one odd number and one even number, and the sum of an odd number plus an even number is always an odd number.