To write this algebraically:
2x+18>25
and solve:
2x>25-18
x>7/2
Therefore x (a number) must be greater than 7/2.
x = 11
44
Consider 4 cases 1. The sum of any two positive numbers is clearly greater than either number. 2. The sum of any two negative numbers is LESS than either of the two numbers. ( (Look at -2+(-3)=-5 .) 3. The sum of any negative number and a positive number is always greater than the negative number but less than the positive number. (Look at -2+3=1, or -5+3=-2) 4. The sum of any number and 0 is that number so it is not greater. So it appears that the sum of any two numbers is greater than either of the two numbers when the two number are both positive.
Given an arbitrary odd natural number greater than five, x, let y = x - 3, then y is an even number greater than 2. By assumption we have that y is the sum of two primes, say y1 and y2, but then x = y1 + y2 + 3 (which is the sum of three primes).
To write twice the sum of a number and 600, you first express the number as a variable, such as ( x ). The sum of the number and 600 can be written as ( x + 600 ). Therefore, twice this sum is represented as ( 2(x + 600) ).
2a+3>49
2n + 3 > 49 n > 23
Let the number be x and so: 2x+3 > 49
9218 9425
Not always, if the smaller number is 0 or a negative number. Then their sum will be equal or less than the greater number.
20
8 greater than the original number.
18
11,33
Correction: Here is the equation you will need to solve: 7N - 30 = 2N + 5 --> 5N = 35 --> N = 7
x = 11
a deficient number is greater than the sum of its proper divisors