The number is 17.
The sum of -18 and 39 is 21.
39.
To find the average, add up all the numbers and then divide the sum by the number of numbers you added. 7+11+21=39 39/3=13 The average is 13.
Let the five numbers be ( x_1, x_2, x_3, x_4, x_5 ). The mean of these numbers is 39, so their total sum is ( 5 \times 39 = 195 ). When one number is excluded, the mean becomes 35 for the remaining four numbers, giving a total sum of ( 4 \times 35 = 140 ). Therefore, the excluded number is ( 195 - 140 = 55 ).
23 * 16 = 368
39
46
3n + 6 = 39Therefore 3n = 39 - 6 = 33n = 33 / 3Therefore, n = 11
If the larger number can be anything more than twice the smaller number, then the two numbers can be:1 + 45 = 463 + 43 = 465 + 41 = 467 + 39 = 469 + 37 = 4611 + 35 = 4613 + 33 = 4615 + 31 = 46
39
6
let x be one number and y be the other The first thing given is that x is 3 less than twice y so x=2y-3 and x+y=39 so x=39-y and substitute this into the first equation a 39-y=2y-3 42=3y y=14 and x=39-14 or 25 Answer x=25 and y=14 Now lets check it 25 is 3 less than 2x14 (YES) 14+25=39 (YES) Done
The sum of -18 and 39 is 21.
39.
89
To find the average, add up all the numbers and then divide the sum by the number of numbers you added. 7+11+21=39 39/3=13 The average is 13.
4x-39 = 2x+3, 4x-2x = 42 x=21