If the two numbers have a hcf of 48 then both numbers must be multiples of 48.
384 ÷ 48 = 8 .........Taking the paired factors of 48 of both numbers then the sum of the other factors = 8 but there can be no other common factor.
1 + 7 = 8, 3 + 5 = 8 are solutions but 2 + 6 = 8 and 4 + 4 = 8 are not, as further common factors of 2 and 4 respectively are present which would increase the hcf to 96 and 192.
The numbers are 1 x 48 and 7 x 48 → 48 and 336
and.....................3 x 48 and 5 x 48 → 144 and 240
No, it is impossible.
Not possible in whole numbers
1394
That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).
The sum of three odd numbers will be odd, whether they are prime or not. The sum of three prime numbers can be even as long as one of them is 2.
HCF of 17 and 68 is 17 ..( Lowest Prime factor ) LCM Of 102 and 476 is 7*2^2*3*17 which is 1428 .. ==> Sum of HCF and LCM are 1428+17= 1445 .
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
The HCF of the given three numbers is 9 and because the digital sum of the given numbers equals 9 then the numbers are all divisible by 9
48 & 336; 144 & 240; For inf, this was calculated by dividing 384 by 48, giving 8. This means that the numbers sought are multiples of 48 by two numbers totalling 8. 1/7 and 3/5 are the only answers which fit the question as 2/6 would mean the HCF was 96 (96 and 288).
No
No, it is impossible.
Not possible in whole numbers
1394
5678 + 8765 = 14443 would yield the largest possible sum.
That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).
The sum of three odd numbers will be odd, whether they are prime or not. The sum of three prime numbers can be even as long as one of them is 2.
Their product.