Wiki User
∙ 14y agoIf that's 32.1 meters per second initially, then after 4 seconds it's falling
with a speed of 7.1 meters per second.
If that's 32.1 feet per second initially, then it returns to the thrower's hand in
just under 2 seconds, and it's in the dirt long before 4 seconds have passed.
If it had been tossed at the edge of a cliff, then after 4 seconds, it would be
falling with a speed of 96.7 feet per second.
Wiki User
∙ 14y agoIgnoring air resistance and using g = 9.81 ms-2, velocity = 20.38 ms-1.
V = V0 + a t V0 = + 32.1 m/sec a = - 9.78 m/sec2 t = 4 sec V = (32.1) + 4 (-9.78) = (32.1) - (39.12) = - 7.02 m/sec (7.02 m/sec downward)
When an object falls vertically downward, its velocity increases according to the following equation:2aS=vf2 - vi2 or ,2*10*S=v2, orv=(20S)1/2.There is a second case in which a body is thrown vertically upward, here its velocity decreases as it moves upward. Here its velocity becomes zero as it reaches the highest point
if the bal is thrown by making 45 degree angles. with the ground..it will travel maximum distance...
30 mph!
Ignoring air resistance and using g = 9.81 ms-2, velocity = 20.38 ms-1.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
At the highest point, the velocity of an object thrown vertically into the air is momentarily zero as it changes direction. This is the point where it transitions from going upward to downward.
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
The ball is affected by the force of the earth's gravity.
The ball is affected by the force of the earth's gravity.
To draw a velocity-time graph for a body thrown vertically upwards, the initial velocity will be positive (upwards) and steadily decrease due to gravity until reaching zero at the peak. After the peak, the velocity becomes negative as the body falls back down. The graph will have a symmetrical shape with the velocity decreasing and then increasing back to the initial velocity.
The ball is affected by the force of the earth's gravity.
In the case of constant velocity (or speed), velocity = distance / time.
At the highest point of its trajectory, a ball thrown vertically upwards has zero velocity. Since momentum is the product of velocity and mass, the momentum of the ball at the highest point is also zero.
The vertical component of the initial velocity of the ball thrown horizontally from a window is zero. The ball's initial velocity in the vertical direction is influenced only by the force of gravity, not the horizontal throw.
A baseball thrown with little velocity to fool a hitter is called a changeup. Also known as a change, changay or change-piece.