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Well, if there are twice as many boys as girls in a group of 120 children, that means there are 80 boys and 40 girls. So, there are 40 girls in the group. Math doesn't lie, honey.
If there are 55 children in the classroom then it is not possible for 61 of them ti be girls!
Well, isn't that a happy little math problem we have here? Since the boys outnumber the girls by 2 to 1, we can think of the ratio as 2 parts boys to 1 part girls. If we have 30 children in total, that means there are 20 boys and 10 girls in the class. Just imagine all those little painters creating beautiful artwork together!
4/5 of the children are boys. So 1 - 4/5 ie 1/5 of the children are girls. 1/5 = 100 so 1 = 500 ie there are 500 children in all. 4/5 of 500 is 500*4/5 = 400 So there are 400 boys.
Let the number of girls be ( x ). Since there are three times as many boys as girls, the number of boys is ( 3x ). Together, the total number of children is ( x + 3x = 4x ). Setting this equal to 80 gives us ( 4x = 80 ), so ( x = 20 ). Therefore, there are 20 girls in the group.
they may be girls and boys
1000:4000
1000 :4000
Both.
Well, if there are twice as many boys as girls in a group of 120 children, that means there are 80 boys and 40 girls. So, there are 40 girls in the group. Math doesn't lie, honey.
No, Because if they were boys would of distracted the girls or maybe opposite.
189 boys
2 boys 1 girl
BOYS !
51 girls, 29 boys
The girls had to learn in school.
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