P(red star) = 4/15
P(green star) = 2/14
P(red, green) = (4/15)(2/14) = 8/210=4/105
a black one
There are 8 marbles that aren't black, out of a total of 12 marbles, so the probability is 8/12 or 2/3.
The probability is zero, because there are no red balls in the bag.
No comment
25%
a black one
There are 8 marbles that aren't black, out of a total of 12 marbles, so the probability is 8/12 or 2/3.
The probability is zero, because there are no red balls in the bag.
No comment
25/50 gives the probability of selecting a blue marble
The theoretical probability of randomly drawing a green marble can be calculated by dividing the number of green marbles by the total number of marbles in the bag. In this case, there are 12 green marbles out of a total of 5 red marbles + 8 blue marbles + 12 green marbles, which is 25 marbles in total. Therefore, the theoretical probability of drawing a green marble is 12/25 or 48%.
The probability is 0.56
25%
The probability is orange / total * red / total, which equals one fortieth. 5/40*8/40 = 40/1600 = 1/40
This is a law of addition probability which states that the probability of A or B equals the probability of A plus the probability of B minus the probability of A and B. Written in mathematical terms, the equation is: P(AorB) = P(A) + P(B) - P(AnB) where P(AnB) = 0 (since you can not pull out a green and black ball at the same time). Let P(A) = Probability of drawing the green ball & let P(B) = Probability of drawing the black ball. Total outcomes is 17. So, P(A) = 4/17 & P(B) = 6/17. Therefore P(green or black) = 4/17 + 6/17 = 10/17.
The probability is 19/25 * 18/24 = 0.57
Step 1: Count the total number of sweets in a "bag"There are 3 yellow, 5 green, 7 red, 4 purple and 1 black sweets. Add all these values up to obtain 20 sweets total.Step 2: Determine the probability of the given eventSince we want to determine the probability of selecting a black sweet out of a "bag", we have:1 / 20 = number of black sweets / total number of sweets