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Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
If Andy has 16 coins. Some of them are dimes and some are nickels. The combined value of his dimes and nickels is 1.35. How many dimes and nickels does he have?
11 dimes and 5 nickels.
How many nickels and dimes worth 1.65?
Let's represent the number of nickels as 'n' and the number of dimes as 'd'. The value of n nickels is 0.05n, and the value of d dimes is 0.10d. We can set up the equation 0.05n + 0.10d = 1.65 to represent the total value of the coins. Solving this equation will give us the values of n and d.
When a piggy bank has 160 total coins valuing 10.50. Think about a system of equations that can be used to represent the number of nickels and dimes and then think through?
If n is the number of nickels and d the number of dimes, then the equations are:n + d = 160 (total number of coins) 5n + 10d = 1050 (total value). And I have thought through to the answer.
A boy has twice as many nickels as dimes and 5 more half dollars than nickels If the total value of the coins is 6.10 how many of each coin has he?
there r 40 nikels
Nick has 35 coins consisting of dimes and nickels If the value of the coins is 3.10 then how many dimes does he have?
he has 27 dimes. to add on, he has 8 nickels to make your total of 3.10
Jimmy had 15 coins in his pocket they were dimes and nickels the total value of the coins was 1.30 how many dimes did he have in his pocket?
11 dimes.
Ms Lynch has 21 coins in nickels and dimes Their total value is 1.65 How many of each coin does she have?
ms lynch has 21 coins in nickels and dimes. their total value is 1.65. how many of each coin does she have
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
Anthony has 10 coins consisting of dimes nickels and pennies Total value is 62 cents what coins does Anthony have?
Tjats a pretty simple question. Anthony has. 2 pennies, 4 dimes, and 4 nickels
If Andy has 16 coins. Some of them are dimes and some are nickels. The combined value of his dimes and nickels is 1.35. How many dimes and nickels does he have?
11 dimes and 5 nickels.
A piggy bank contains only nickels and dimes In all there are 42 coins with a total value of 3.85 How many nickels are in the piggy bank?
7
How many nickels and dimes worth 1.65?
Let's represent the number of nickels as 'n' and the number of dimes as 'd'. The value of n nickels is 0.05n, and the value of d dimes is 0.10d. We can set up the equation 0.05n + 0.10d = 1.65 to represent the total value of the coins. Solving this equation will give us the values of n and d.
How many dimes does Joe have if a collection of nickels and dimes that is worth 6.05 If the number of dimes was doubled and the number of nickels was decreased by 10 the value coins would be 9.85?
Ten it each group.
When a piggy bank has 160 total coins valuing 10.50. Think about a system of equations that can be used to represent the number of nickels and dimes and then think through?
If n is the number of nickels and d the number of dimes, then the equations are:n + d = 160 (total number of coins) 5n + 10d = 1050 (total value). And I have thought through to the answer.
A boy has twice as many nickels as dimes and 5 more half dollars than nickels If the total value of the coins is 6.10 how many of each coin has he?
there r 40 nikels
10 coins consistinig of nickels and dimes equal 80 cents how many coins does she have?
You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.
