The equation of a circle in standard form is given by ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center of the circle and (r) is the radius. For a circle centered at the point (3, 2) with a radius of 5, the equation is ((x - 3)^2 + (y - 2)^2 = 5^2). Simplifying this, we get ((x - 3)^2 + (y - 2)^2 = 25).
x2 + y2 = 49
The equation you provided, (x^2 + y^2 = 100), represents a circle centered at the origin (0,0) with a radius of (r = \sqrt{100} = 10). Therefore, the length of the radius of the circle is 10 units.
1.6667
The equation of a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this case, since the radius is 10, the equation becomes ( x^2 + y^2 = 10^2 ). Therefore, the equation of the circle is ( x^2 + y^2 = 100 ).
The equation of a circle centered at the origin (0, 0) with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). For a circle with a radius of 3, the equation becomes ( x^2 + y^2 = 3^2 ), which simplifies to ( x^2 + y^2 = 9 ).
x2 + y2 = 25
x2 + y2 = 25
x2 + y2= 16
x2 + y2 = 49
x2 + y2 = 36
The equation you provided, (x^2 + y^2 = 100), represents a circle centered at the origin (0,0) with a radius of (r = \sqrt{100} = 10). Therefore, the length of the radius of the circle is 10 units.
Equation of circle: (x+2)^2 +(y+3) = 49
1.6667
The equation of a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this case, since the radius is 10, the equation becomes ( x^2 + y^2 = 10^2 ). Therefore, the equation of the circle is ( x^2 + y^2 = 100 ).
The equation of a circle centered at the origin (0, 0) with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). For a circle with a radius of 3, the equation becomes ( x^2 + y^2 = 3^2 ), which simplifies to ( x^2 + y^2 = 9 ).
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Equation of circle: (x-3)^2 +(y-2)^2 = 49