Três números consecutivos iguais a 369 são 122, 123 e 124.
Para encontrar esses números, podemos utilizar a fórmula:
(n-1) + n + (n+1) = 369
Resolvendo a equação, encontramos que n = 123. Portanto, os três números consecutivos são:
n-1 = 122 n = 123 n+1 = 124
Let the number be 'n-1' , N & n+ 1'.
Hence
(n-1) + n + ( n + 1) = 369
Add the LHS
3n = 369
n = 369/3
n = 123
Hence n-1 = 122
& n + 1 = 124
So the three consecutive numbers are
122,123,124.
"Average" number must be 369/3 ie 123 so numbers are 122, 123 and 124
It is impossible to add nine consecutive whole numbers to make 375. The results closest to 375 are the sum of the numbers 37 to 45 (369), and the sum of the numbers 38 to 46 (378).
369 is composite because 3 and possibly other numbers besides 1 and 369 are factors of 369.
369/3 = 123
0.1138
1, 3, 9, 41, 123 and 369.
The numbers are 122, 123, 124 as well as 121, 123, 125.
It is impossible to add nine consecutive whole numbers to make 375. The results closest to 375 are the sum of the numbers 37 to 45 (369), and the sum of the numbers 38 to 46 (378).
3.69 is equal to 369/100, or three hundred and sixty nine hundredths.
369 is composite because 3 and possibly other numbers besides 1 and 369 are factors of 369.
369
369/3 = 123
1, 3, 9, 41, 123, 369.
1, 3, 9, 41, 123 and 369.
0.1138
738
(123,3) and (41,9)
-73