Q: Three numbers in GP sum up to 21. Their product is 216. Find the numbers?

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the sum of three consecutive numbers is 216. What are the three numbers?

23 x 33 = 216

6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.

divide 216 by 3 (72) subtract 1 and add 1 71, 72 and 73

For 216 the numbers are 70, 72 and 74. For 238 the numbers are 58, 59, 60 and 61.

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71 + 72 + 73 = 216

216 = 2x2x2x3x3x3

the sum of three consecutive numbers is 216. What are the three numbers?

71,72,73 :)

23 x 33 = 216

6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.

As a product of its prime factors expressed in exponents it is: 23*33 = 216

divide 216 by 3 (72) subtract 1 and add 1 71, 72 and 73

The numbers are 71, 72 and 73.

For 216 the numbers are 70, 72 and 74. For 238 the numbers are 58, 59, 60 and 61.

x+x+1+x+2=216 3x+3=216 3x=213 71,72,73

215 + 216 + 217 + 218 = 866