Trying to figure something out. I have a three digit combination and it looks like this. 012345 012345 012345 I need all the possible three digit combinations like 000 or 001 or 345 like that.?

Answer 1

As you describe the problem, the condition is you can select any of the 6 numbers with replacement since you have 3 sets of numbers for each value. Per the related link, you have N = 6 and n = 3. The number of combinations is Nn, or 63, or 216. If it is easier to think of the problem in this way, here is another way to look at it. You have 6 choices for the first digit, 6 choices for the second digit, and 6 choices for the third digit. So, you have 6*6*6 = 216 combinations.

Answer 2

To generate all possible three-digit combinations from the given pattern, you can start from 000 and increment by 1 until you reach 999. Here's an example:

000
001
002
...
345
...
998
999

Continue this pattern, incrementing each digit by 1 until all possible combinations have been generated.