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Depends of what the twenty something is. But i can help a bit.
=> 20ish + 5x = 35
{take 20ish from both sides of the equation}
=> 5x = 35 - 20ish
{divide both sides of the equation by 5}
=> x = (35 -20ish) /5
Just replace the 20ish with the exacty number and do the calcuation e.g. if it was exactly 20 the x = (35 - 20) / 5 = 15/5 = 3.
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