4n - 10 = 38 (add 10 to both sides)4n = 48 (divide by 4 to both sides)n = 12
Yes, twice
XXXVIII is '38' That is x = 10 x = 10 x = 10 V = 5 I = 1 I = 1 I = 1 Add 10 + 10 + 10 + 5 + 1 + 1 + 1 = 38
The number you've provided is 10^38, which is read as "10 to the power of 38" or "1 followed by 38 zeros." In scientific notation, it is written as 1 x 10^38. This number is extremely large and represents a septillion in the American numbering system.
38
4n - 10 = 38 (add 10 to both sides)4n = 48 (divide by 4 to both sides)n = 12
124 - 38 /2 = 86/2 = 43
If the number, x, has 10 subtracted from twice it to make 28, then x must be 19. 2x - 10 = 28 2x = 38 x = 19
304. Each number is twice the previous number.
to get the answer, divide 152 by 4 and then multiply by 5, so 152 divided by 4 = 38 38 x 5 = 190
2x = 76 x = 38
1/3x - 11 = 38 Therefore, 1/3x = 49 Therefore, x = 49 x 3 = 147
380
4x + 10 = 384x = 38 - 104x = 28x = 28/4Therefore, x = 7.
The number that goes into both 38 and 57 is 19. This is because 38 divided by 19 equals 2, and 57 divided by 19 equals 3. In other words, 19 is a common factor of both 38 and 57.
18 and 38
18 and 38