The sum of all three internal angles is 180 degrees so, if two of them are 40 degrees each the third must be ...
In a triangle, the sum of all three angles is always 180 degrees. If two angles measure 32 degrees each, their total is 64 degrees. To find the measure of the third angle, subtract 64 from 180, which gives you 116 degrees. Therefore, the measure of the third angle is 116 degrees.
96 degrees
The three angles always add to 180, so the third angle would be 40 degrees.
If you mean the equal angles were each 70o then 180 - 140 ie 40o
60 degrees
If two angles of a triangle each measure 55 what is the measure of the third angle?
180- total of the first two angles= 3rd angle
The sum of the angles is 180 degrees in any triangle. So 180-140 is 40 and the third angle is 40 degrees.
90 degrees
In a triangle, the sum of all three angles is always 180 degrees. If two angles measure 32 degrees each, their total is 64 degrees. To find the measure of the third angle, subtract 64 from 180, which gives you 116 degrees. Therefore, the measure of the third angle is 116 degrees.
96 degrees
The three angles always add to 180, so the third angle would be 40 degrees.
110180 - (2 x 35) = 110
90 degrees
If you mean the equal angles were each 70o then 180 - 140 ie 40o
55Improved Answer:-It is: 180-54-54 = 72 degrees
Let the measure of the first angle be x⁰. So that the second angle would be (x + 21)⁰, and the third one would be (x - 15)⁰.Since the sum of angle measures in a triangle is 180⁰ we have:x + x + 21 + x - 15 = 1803x = 174x = 58Thus, the first angle is 58⁰, the second angle is 79⁰, and the third angle is 43⁰.