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Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? A. 2 hours
B. 4 ½ hours
C. 5 ¾ hours
D. 6 hours
E. 7 ½ hours Answer
The distance the 1st cyclist travels is 6(3+t) miles, and
the distance the 2nd cyclist travles is 10t miles...
where t=the number of hours since cyclist #2 starts.
Now solve: 6(3+t)=10t ==> 18+6t=10t ==> 18=4t ==> t=4.5 hrs
==> 4.5 hours = 4 hrs 30 minutes
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Two cyclists start biking on a trail. Cyclist 2 travels at 10 mph and starts 3 hours after cyclist 1 who is traveling at 6 mph. How much time does it take for cyclist 2 to catch cyclist 1?
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