The remainder is not zero so y-3 is not a factor of y^4+2y^2-4
we can use direct substitution. do this we must take the opposite of the constant in the factor that we want to test. -1*(1)=-1 now we simply take f(-1). =-1^3-(-2)^2-8(-1)-5 =-1-4+8-5 =-2 since we got -2 in the end (x+1) is not a factor of this polynomial. According to factor theorem it can only be a factor is the remainder is 0
If N is the number, and f is the number that you want to test as a possible factor, then first of all:test N > f (this must be true, the factors are always smaller in magnitude)next perform N ÷ f (N divided by f). If the quotient (answer to a division problem) is a whole number with no remainder or fractional part, then f is a factor of N.If the quotient is not a whole number (meaning there is a remainder), then f is not a factor.
To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.
Add up the digits of 291. If they total a multiple of 9, 9 is a factor.
Yes, that's correct. According to the Factor Theorem, if a polynomial ( P(x) ) is divided by ( (x - a) ) and the remainder is zero, then ( (x - a) ) is indeed a factor of the polynomial. This means that ( P(a) = 0 ), indicating that ( a ) is a root of the polynomial. Thus, the polynomial can be expressed as ( P(x) = (x - a)Q(x) ) for some polynomial ( Q(x) ).
In algebra, the factor theorem is a theorem linking factors and zeros of a polynomial. It is a special case of the polynomial remainder theorem.The factor theorem states that a polynomial has a factor if and only if
In algebra, the factor theorem is a theorem linking factors and zeros of a polynomial. It is a special case of the polynomial remainder theorem.The factor theorem states that a polynomial has a factor if and only if
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Divide the smaller number into the bigger number. If the answer comes out even with no remainder, it's a factor.
Divide the larger number by the smaller. If the result has no remainder (no decimal) then the smaller number is a factor of the larger.
we can use direct substitution. do this we must take the opposite of the constant in the factor that we want to test. -1*(1)=-1 now we simply take f(-1). =-1^3-(-2)^2-8(-1)-5 =-1-4+8-5 =-2 since we got -2 in the end (x+1) is not a factor of this polynomial. According to factor theorem it can only be a factor is the remainder is 0
To find out if 7 is a factor of 2395, divide 7 into 2395 and you'll get 342 and a remainder of 1. This means 7 is not a factor of 2395.
Remainder Theorem:- When f(x) is divided by (x-a) the remainder is f(a) Tor example:- f(x) x3-2x2+5x+8 divided by x-2 f(2) 8-8+10+8 = 18 So the remainder is 18 if there is no remainder then the divisor is a factor of the dividend.
Divide 7 into 29. If the answer is an integer with no remainder, it's a factor.
If N is the number, and f is the number that you want to test as a possible factor, then first of all:test N > f (this must be true, the factors are always smaller in magnitude)next perform N ÷ f (N divided by f). If the quotient (answer to a division problem) is a whole number with no remainder or fractional part, then f is a factor of N.If the quotient is not a whole number (meaning there is a remainder), then f is not a factor.
To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.
You determine all numbers that will can be divided evenly (without a remainder) into the object numbers. The highest number doing that is the common factor.