axb + cxd
The equation ( \log_A 6 = B ) can be rewritten using exponents as ( A^B = 6 ). If we also have ( a^b = c ), we can express ( A ) as ( a ), ( B ) as ( b ), and ( 6 ) as ( c ). Thus, ( a = A ), ( b = B ), and ( c = 6 ).
(start) /a=0 c=0\ \b=0 / /input a/ /input b/ /input c/ /a>b\ no /b>c\ yes /display b/ -> (a) \ / \ / yes no /a>c\ no /display c/ -> (a) \ / yes /display a/ <- (a) (end)
max = a > b ? a : b; max = max > c ? max : c;
dim a,b,c a=cint(inputbox("enter value for a")) b=cint(inputbox("enter value for b")) c=cint(inputbox("enter value for c")) if((a>b)and(a>c)) then msgbox "greatest number is a="&a else if ((b>a)and(b>c)) then msgbox "greatest number is b="&b else msgbox "greatest number is c="&c end if end if
If you know the lengths of two sides, a and b, and the included angle, C, then area = 0.5*a*b*sin(C)
The equation ( \log_A 6 = B ) can be rewritten using exponents as ( A^B = 6 ). If we also have ( a^b = c ), we can express ( A ) as ( a ), ( B ) as ( b ), and ( 6 ) as ( c ). Thus, ( a = A ), ( b = B ), and ( c = 6 ).
If a + b = cThen a = c -b
a=a^b; b=a^b; a=a^b;
A)Testing and debugging difficulty B)Deadlocks C)Data races D)B and C E)A, B and C Any one?
biggest3 (a,b,c) = biggest2 (a, biggest2 (b,c))
(start) /a=0 c=0\ \b=0 / /input a/ /input b/ /input c/ /a>b\ no /b>c\ yes /display b/ -> (a) \ / \ / yes no /a>c\ no /display c/ -> (a) \ / yes /display a/ <- (a) (end)
(a+b).c=(a.b)+(b.c) (a+b).c=(a.b)+(b.c)
You use a person's name to spell it.
mga bogo man mo ///// c HAPAY NI ,,
int min (int a, int b, int c) {if (a
In logical circuits, the expression A BA C can be simplified using Boolean algebra. The term "BA" suggests that it involves an AND operation between A and B, while C is combined using an OR operation. Therefore, the expression simplifies to A AND B OR C, which can be written as (A ∧ B) ∨ C. This means that the output is true if both A and B are true, or if C is true.
R = (A > B && A > C) ? A : (B > C) ? B : C; // parentheses not necessary - for clarity only