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117 is a composite. I know because suming the digits is 9. A number is a multiple of 117 if it's a multiple of 9 and 13 at the same time
To keep it simple: Write a main loop that goes through all the numbers, starting with 2, and incrementing one at a time. Determine whether each number is a prime number. If it is, increment a counter. To determine whether each number is a prime number, either use an inner loop, or a separate function. Test divisibility of the number "n" by every number from 2 to n-1. If you find a factor, then it is not a prime number. Note that you can test divisibility by using the "%" operator. For example: if (number % factor == 0) // number is divisible by factor else // it isn't
all digits in the number must total to a number divisible by 3 when added up e.g 156=1+5+6=12 which is divisible by 3 you can proove this using other numbers eg 39,24,1107 e.t.c
Yes, 104 is a multiple of four. You can tell by using the divisibility rules : if the last two digits of a number are divisible by four, then the whole number is divisible by four. Now lets go back, in case you don't know, divisibility is simply if a smaller number, like four, can go into a larger number, like 104, perfectly;without having to use decimals.
Yes, you can. Using the divisibility rules, you can quickly tell that 87 is divisible by 3 (the digits add up to 15, which is divisible by 3). 3 x 29 = 87