answersLogoWhite

0


Best Answer

The volume of HCP is 8*pi*r^3

or 25.13*r^3

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Volume of a HCP unit cell?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How do you calculate APF of HCP?

The atomic packing factor (APF) of a hexagonal close-packed (HCP) structure is calculated by taking the volume of atoms in a unit cell divided by the total volume of the unit cell. For HCP, the APF can be determined using the formula: APF = (3 * sqrt(3) * (0.25)) / (2 * sqrt(2)) This simplifies to APF = 0.74


Number of atoms in hcp unit cell?

In a hexagonal close-packed (hcp) unit cell, there are a total of 6 atoms. This includes 3 atoms at the corners of the base layer, 1 atom at the center of the base layer, and 2 atoms on the top layer above the center atom.


What is the difference between hcp and ccp closed packing?

HCP (hexagonal close-packed) and CCP (cubic close-packed) are both types of close-packed crystal structures. The main difference lies in the arrangement of atoms - HCP has two alternating layers of atoms, while CCP has three alternating layers. HCP has a hexagonal unit cell, while CCP has a cubic unit cell.


How do you calculate the volume of a HCP crystal?

Are you takling Material Science class? Volume of HCP crystal = (a^2) (c) cos30 Im taking Material Science and Engineering


What is the best unit to measure a cell membrane?

volume


How do you calculate the Volume of unit cell of Bcc?

The volume of a Body-Centered Cubic (BCC) unit cell can be calculated using the formula: Volume = a^3 * sqrt(3) / 2, where 'a' is the edge length of the unit cell.


How do you calculate density of MgO?

Density can be calculated as the mass per a certain amount of volume. There are equations avaible to find the mass per unit cell as well as the volume of a unit cell such as d = (#particles/unit cell)(AW, g/mol)/(avagado's #)(edge legnth)^3


What is the calculations of the density of gold based on the unit cell. The face-centered gold crystal has an edge length of 407 pm?

The face-centered cubic unit cell of gold contains 4 atoms. The volume of the unit cell can be calculated using the formula V = a^3, where a is the edge length. Then, the mass of the unit cell can be calculated using the density of gold. Finally, the density of gold can be calculated by dividing the mass of the unit cell by its volume.


What is the Lewis structure for HCP?

The Lewis structure for hexagonal close-packed (HCP) structure cannot be accurately represented using the traditional Lewis dot structure as it is a three-dimensional arrangement of atoms. HCP structure consists of layers of atoms arranged in a hexagonal pattern with every other layer shifted by half the length of the unit cell along the c-axis.


Describe what is meant by each of the following terms cell volume cell surface area ratio of surface area to volume?

A cell's volume is the amount of material that can fit into the cell. A cell's surface area is the total amount of material that makes up the outside of the cell. The ratio of surface area to volume is the amount of surface area per unit volume of an object or collection of objects.


Crystalline silicon has a cubic structure the unit cell edge is 543pm calculate the number of unit cells per cubic cm?

To calculate the number of unit cells per cubic cm, we need to determine the volume of a single unit cell. Since it's a cubic structure, the volume of the unit cell would be (edge length)^3. Converting 543 pm to cm (1 pm = 1x10^-10 cm) and then calculating the volume, we get approximately 1.53x10^-22 cm^3. Finally, to find the number of unit cells per cubic cm, we divide the volume of the cube (1 cm^3) by the volume of the unit cell. So, 1 cm^3 / 1.53x10^-22 cm^3 equals approximately 6.53x10^21 unit cells per cubic cm.


How many Ca atoms are in one unit cell?

In a face-centered cubic (FCC) unit cell, there are 4 calcium (Ca) atoms located at the corners of the cell, each contributing 1/8 of its volume. There is also another Ca atom located at the center of the cell, contributing the entire volume. Therefore, there is a total of 4 + 1 = 5 calcium atoms in one FCC unit cell.