It's a cylinder on its side, so v = pir2h = 5pi = Approx 15.7 cuft
Taking pi as 3.14159So, that's essentially a cylinder dia. 4ft. * 6 ft. long, and a sphere dia. 4 ft.1.) cylinder = pi * r2 * length = 3.14159 * 4 * 6 = 75.3982 cubic ft.2.) sphere = 4/3 * pi * r3 = 4/3 * 3.14159 * 8 = 33.5103 cubic feetTotal = 75.3982 + 33.5103 = 108.9085 cubic feet
the volume of the storage tank is 21,195 ft.3 (pi times radius2)times height.
An aquarium is 10 ft long, 3 ft wide, and is filled with water to a depth of 7 ft. Water weighs 62.4 pounds per cubic foot. What is the volume and weight of the water in the tank
If you multiply the numbers for length x depth x width, you will get the volume in cubic feet.
Volume = pi*r2*h = 1696.5 cubic feet (approx).
height = 8000/pi*122
aprox 400 gal i have a 4 ft dia tank that's 6 ft long it holds 200 gal
V = 2,269.8 cubic feet.
21
Taking pi as 3.14159So, that's essentially a cylinder dia. 4ft. * 6 ft. long, and a sphere dia. 4 ft.1.) cylinder = pi * r2 * length = 3.14159 * 4 * 6 = 75.3982 cubic ft.2.) sphere = 4/3 * pi * r3 = 4/3 * 3.14159 * 8 = 33.5103 cubic feetTotal = 75.3982 + 33.5103 = 108.9085 cubic feet
the volume of the storage tank is 21,195 ft.3 (pi times radius2)times height.
In complete data. Any way let us assume the cross section of the tank is a sqaure of side 60 ft. Then its area would be 3600 ft2. So its volume would come to 3600 ft3
Volume of tank is needed. Let's assume volume of tank = V ft^3 Rate of pump = 100/0.5 ft^3/hr = 200 ft^3/hr To solve for time: V ft^3 X hr/200 ft^3 = T hr
An aquarium is 10 ft long, 3 ft wide, and is filled with water to a depth of 7 ft. Water weighs 62.4 pounds per cubic foot. What is the volume and weight of the water in the tank
If you multiply the numbers for length x depth x width, you will get the volume in cubic feet.
A "16 ft tank" does not tell us it's volume.
Volume = pi*r2*h = 1696.5 cubic feet (approx).