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80x Each member is 8 (not 80) times the previous one.
√(10x) * √(8x) = √(80x²)√(80x²) = √(16x²) * √(5) = 4x*√(5)■
It's an equation. If you're looking for the value of x, you can solve it like this: x + 3 = 80x + 4 x = 80x + 1 -79x = 1 x = -1/79
If: y = 20 -x and x^2 +y^2 = 80 Then: x^2 +(20-x)^2 = 80 Multiplying out the brackets: x^2 +400 -80x +4x^2 = 80 Transposing terms: 5x^2 +320 -80x = 0 Divide all terms by five: x^2 +64 -16x = 0 Factorizing: (x-8)(x-8) = 0 => x = 8 and x = 8 By substitution point of contact is at: (8, 4)