y=x+1,0=x+1,-1=x...y=x+1,y=0+1,y=1...y=x+1=(-1,1)
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Not sure what all the above stuff means. In any case, it is wrong.
y = x + 1 is the equation of a straight line, and the coordinates of ANY of the infinite number of points on that line are a solution to the equation.
1
The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
solution: y = 0 x = -1
y - 1
Yes, if x and y = 1 √1 + √1 = √1 + 1 1 + 1 = 1 + 1 QED
1
(1, 9)
y=x+1 there for answer is 2
In the equations Y=X-1 and Y=-X+1, the solution is (1,0)
The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
solution: y = 0 x = -1
If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.
y - 1
When x = 1 then y = 4
The solution is: x = 1 and y = -1
y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1
It is (-1, 3).