Suppose m and n are integers. Then 2m+1 is an odd number and 2n is an even number.(2m + 1) * 2n = 4mn + 2n = 2*(2mn + 1).
Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + 1 is an integer. Thus the product is a multiple of 2: that is, it is even.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Even times odd is odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Even times odd is even/
it would be even. for example 2 times 3 equals 6 and 11 times 20 equals 220 so it would be even
Yes. One has to be the square of an odd number. The other square has to the the square of the even number either before or after the odd number. If this is confusing just plug in real values. In either case, an odd times and odd is odd. Therefore one of the squares has to be odd. AN even times an even, however, is always even. Therefore, the second square has to be even. Thus, one of the squares is even and the other is odd. An even plus and odd is always odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times odd is always odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times even is even.
That happens because 5 is an odd number. An odd number times an odd number will give you an odd product; an odd number times an even number will give you an even product. The same happens for the multiples of any other odd number.
No. In fact, you NEVER get an odd number.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times even is even.
Even, anything times an even = an even
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
The product of multiplication results in a number that has all of the factors of the two numbers being multiplied. All even numbers have the prime factor 2. Since no odd number has the factor 2, no product of those numbers can have it. So: - Odd numbers times odd numbers produce odd numbers. - Odd numbers times even numbers produce even numbers. - Even numbers times even numbers produce even numbers.
odd * odd = odd answer even * even = even answer odd * even = even answer
There are 3 cases: An even number time an even number such as 2*6=12 is always even. Proof: Since even numbers can be expressed as 2*X and 2*Y, their product is 4xy which is even. An even number times an odd number (same as odd times even) such as 2*3=6 is always even. Proof: 2X represents an even number and 2Y+1 represents an odd number. Their product is 4XY+2X=2(2XY+X), which is even. An odd number times an odd number such as 11*11=121 is always odd. Proof: Let 2X+1 and 2Y+1 be the two odd numbers. Their product is 4XY+2X+2Y+1 = 2(2XY+X+Y)+1, which is odd. Summary: the product of two numbers is always even unless the two numbers are both odd.
"IT IS ALWAYS A ODD"
No, you cannot have an odd number when times by an even number.
5 is an odd number the prime factorization is 1times 5 and 5 times 1numbers which are multiples of 2 are called even no.s and others are odd numbers.