Suppose m and n are integers. Then 2m+1 is an odd number and 2n is an even number.(2m + 1) * 2n = 4mn + 2n = 2*(2mn + 1).
Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + 1 is an integer. Thus the product is a multiple of 2: that is, it is even.
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An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Even times odd is odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Even times odd is even/
it would be even. for example 2 times 3 equals 6 and 11 times 20 equals 220 so it would be even
Yes. One has to be the square of an odd number. The other square has to the the square of the even number either before or after the odd number. If this is confusing just plug in real values. In either case, an odd times and odd is odd. Therefore one of the squares has to be odd. AN even times an even, however, is always even. Therefore, the second square has to be even. Thus, one of the squares is even and the other is odd. An even plus and odd is always odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times odd is always odd.