To find the exponential form of the expression (2x2x2)x(2x2x2x2x2), we need to simplify the expression first and then express it in exponential form. Given expression: (2x2x2)x(2x2x2x2x2) Simplify the expression: (2x2x2) = 2^3 = 8 (2x2x2x2x2) = 2^5 = 32 Now, substitute the simplified values back into the expression: 8 x 32 = 256 Therefore, the exponential form of (2x2x2)x(2x2x2x2x2) is 256.
(2a^2b^2)^3(-7a^13b^2)
The exponential form of 3333 is 3.333 x 10^3.
2x2x3x5x5x5 in exponential form is: 22 x 3 x 53
30 in exponential form is 3 x 101.
3 = 3.0 × 100
3*3*3*3*3
exponential form
3^3
The prime factorization of 336 in exponential form is: 24 x 3 x 7
9^3
It is: 3^7 = 2187