It is: 99/75 times 100/1 = 132%
1*99=992*99=1983*99=2974*99=3965*99=4956*99=5947*99=6938*99=7929*99=89110*99=990...
The number 2 will go into 99 evenly just 49 times, with 1 left over as a remainder.
13
If you count 11 as 2 instances, the digit 1 appears 18 times if you don't count 10, 19 times if you do. 10,11,12,13,14,15,16,17,18,19,21,31,41,51,61,71,81,91
99 ÷ 68 = 1 with remainder 31 or 1.46 times.
It is: 99/75 times 100/1 = 132%
One possible answer is 1 times 99.
The proposition is false. From 1 to 99, the digit 0 is NOT repeated 20 times!
1*99=992*99=1983*99=2974*99=3965*99=4956*99=5947*99=6938*99=7929*99=89110*99=990...
1 plus 9,999 equals 10,000. That is equal to 1,000 x 10.
99 ÷ 14 = 7 with remainder 1 or 7.0714
Since 99 = 100 - 1, 75 x 99 is the same as (75 x 100) - (75 x 1).7500 - 75 = 7425.
The number 2 will go into 99 evenly just 49 times, with 1 left over as a remainder.
To calculate how many times 7 goes into 99, you would perform division. 99 divided by 7 equals 14.142857, which means that 7 goes into 99 approximately 14 times with a remainder of 1. This is because 7 multiplied by 14 equals 98, leaving a remainder of 1 when subtracted from 99.
13
If you count 11 as 2 instances, the digit 1 appears 18 times if you don't count 10, 19 times if you do. 10,11,12,13,14,15,16,17,18,19,21,31,41,51,61,71,81,91