8.98 m
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It is: (151*12)+1 = 1,813 inches in height
To determine the height of the larger bronze statue, we can use the concept of similarity in geometry. Since the statues are similar, their corresponding dimensions are proportional. We can set up a proportion using the masses and heights of the statues: (mass of larger statue)/(mass of smaller statue) = (height of larger statue)/(height of smaller statue). Solving for the height of the larger statue gives us: (2 kg)/(300 g) = (height of larger statue)/(9 cm). Converting the masses to the same units (grams), we get: 2000 g / 300 g = height of larger statue / 9 cm. Simplifying the fraction gives us: 6.67 = height of larger statue / 9 cm. Therefore, the height of the larger bronze statue is approximately 6.67 x 9 cm = 60.03 cm.
The volume of similar figures is proportional to the cube of the any linear dimension (such as the height). Therefore, the "similar model" has a volume of (4/2)3 times 5. Since I didn't convert to common units, the answer will already be in cubic centimeters. If you find this method doubtful, you can do the same, but converting everything to centimeters and cubic centimeters. Reminder: a cubic meter has a million cubic centimeters. In this case, the ratio which you have to cube is 4/200.
You can't since they measure different properties. You cannot express a length in units of volume. It's like asking "what is the height of the Statue of Liberty in cubic meters?".
The number 60 in the bible has several meanings, some of which are: the width and height of the temple of Jerusalem being 60 cubits; the gold statue was 60 cubits high, and St. Paul only accepted 60 year old females to the group of widows.