Two dimes, a nickel, and 10 pennies.
A good question is how do you figure that out. I started out eliminating the coins that could not be included. If one coin was a quarter, the other 12 had to add up to 10 cents. That can't happen so there can't be any quarters in the answer. Then I knew that the number of pennies had to be 0, 5, or 10 since there is no way for the remaining dimes and nickels to to add up to 35 cents if there were another number of pennies.
If you had 5 pennies, then 8 coins would have to add up to 30 cents. Even using all nickels would only use up 6 coins so there had to be more pennies. I then went to 10 pennies and that left 3 coins to get to 25 cents. That's where I came up with 2 dimes, 1 nickel, and 10 pennies.
To make 35 cents in change using five coins, you can use 2 dimes (20 cents), 1 nickel (5 cents), and 2 pennies (2 cents). This combination totals 35 cents. Alternatively, you could also use 3 dimes (30 cents) and 1 nickel (5 cents).
3 dimes and a nickel
To make 35 cents using U.S. coins (pennies, nickels, dimes, and quarters), you can combine different denominations in various ways. For instance, you can use combinations of 1-cent (pennies), 5-cent (nickels), 10-cent (dimes), and 25-cent (quarters) coins. The number of unique combinations depends on the specific limitations placed on each coin type, but a general approach involves calculating combinations systematically or using generating functions. In total, there are 13 distinct combinations to make 35 cents.
A quarter and a dime
quarter and a dime (the other coin is a dime).
If you mean U.S. coins, that would be 25 cents, 5 cents, and 5 cents.
To make 35 cents in change using five coins, you can use 2 dimes (20 cents), 1 nickel (5 cents), and 2 pennies (2 cents). This combination totals 35 cents. Alternatively, you could also use 3 dimes (30 cents) and 1 nickel (5 cents).
3 dimes and a nickel
a quarter and a dime (25c+10c=35c)
a Dime. 10 cents
To make 35 cents using U.S. coins (pennies, nickels, dimes, and quarters), you can combine different denominations in various ways. For instance, you can use combinations of 1-cent (pennies), 5-cent (nickels), 10-cent (dimes), and 25-cent (quarters) coins. The number of unique combinations depends on the specific limitations placed on each coin type, but a general approach involves calculating combinations systematically or using generating functions. In total, there are 13 distinct combinations to make 35 cents.
The answer depends on the currency. The choice of coins for US cents is different to that for Euro cents, so the answer will be different.The answer depends on the currency. The choice of coins for US cents is different to that for Euro cents, so the answer will be different.The answer depends on the currency. The choice of coins for US cents is different to that for Euro cents, so the answer will be different.The answer depends on the currency. The choice of coins for US cents is different to that for Euro cents, so the answer will be different.
A quarter and a dime
quarter = 25 cents dime = 10 cents, total so far 35 cents 2-nickels = 10 cents, total so far 45 cents 3 pennies = 3 cents, total 48 cents
quarter and a dime (the other coin is a dime).
To make 36 cents, you can use various combinations of coins. For example, you could use three dimes and one nickel (30 + 5 = 35 cents) and one penny (1 cent) for a total of 36 cents. Other combinations include one quarter (25 cents) with an additional dime (10 cents) and a penny (1 cent), or combinations of nickels and pennies. The total number of combinations will depend on the specific types of coins you are allowed to use.
it's possible only if there are 20 cent coins only for that 7 dollars 1 dollar = 100 cents, 100 cents = 5 of 20 cent coins since you need 5 of 20 cent coins for a dollar, you do 7 times of it. 7 X 5 = 35. Therefore, you need 35 of 20 cent coins for 7 dollars. (or there are 35 of 20 cent coins in 7 dollars)