The answer depends on the definition of p.
If 12 out of 100 organisms have short legs, P = 0.65.
Without replacement: P(one green and one blue) = P(drawing green then blue) + P(drawing blue then green) = (6/23)(9/22) + (9/23)(6/22) = 104/506 = 52/253 With replacement: P(one green and one blue) = P(green)*P(blue) = (6/23)(9/23) = 54/529
Hold on to your hat! Suppose the rate of depreciation is p percent per year. Current value = Start Value*(1 - percentage/100)years That gives 2047.08 = 5500*(1 - p/100)9 So 0.3722 = (1 - p/100)9 or log(0.3722) = 9*log(1-p/100) -0.4292 = 9*log(1-p/100) -0.0477 = log(1-p/100) 10-0.0477 = 1-p/100 0.8960 = 1-p/100 p/100 = 1 - 0.8960 = 0.1040 and, finally, p = 0.1040*100 = 10.4%
P over B equals R over 100 => P/B = R/100 => P/5950 = 48000/100 => P = 5950 * 480 = 2856000 Or 59.50 * 48000 = 2856000
If the green allele is recessive and there are 28 organisms with green eyes, then the frequency of the green allele (q) would be √(28/Total organisms) = √(28/Total organisms). Since p+q=1, p = 1 - q. Substituting 28 for q gives 1 - √(28/Total organisms).
The answer depends on the definition of p.
If 59 out of 100 organisms are P, then the remaining organisms would be Q. Therefore, Q would be 41 out of 100 organisms.
, 0.34 Apex
If 12 out of 100 organisms have short legs, P = 0.65.
.54
To find q (the frequency of the green allele), use the Hardy-Weinberg equation: p^2 + 2pq + q^2 = 1. Given that 11% are green, q^2 = 0.11. Therefore, q = √0.11 ≈ 0.33.
There are 100 p in a pound so 28p as a fraction of a pound = 28/100 = 7/25
0.16
A. 0.45 Apex
28 meters a2+b2=c2 a2+62=102 a2+36=100 100-36= 64 a2=64 (square root each side) a=8 p=2s+2s p=2(8)+2(6) p=16+12 p=28 meters
To determine ( p ), which represents the proportion of organisms with short legs, you need to know the total number of organisms. If 21 organisms have short legs, and assuming the total number of organisms is ( N ), ( p ) can be calculated as ( p = \frac{21}{N} ). Without the total number, ( N ), you cannot find a specific value for ( p ).