First of all, the question does not require the numbers to be integers. That being the case, there are an infinite number of solutions. One of them being:
So 23 + 33 = (3√35)3
So, 2, 3 and the cibe root of 35 meet the requirements.
If they do need to be integers, then (-1)3 + (1)3 = 03 is a possible solution.
Finally if x, y and z need to be positive integers then
xn + yn = zn does not have a solution for n>2 according to Fermat's last theorem.
The third cubed number is (3^3), which equals (27). Cubed numbers are obtained by raising a number to the power of three, so the first few cubed numbers are (1^3 = 1), (2^3 = 8), and (3^3 = 27). Thus, the third cubed number is 27.
0.3 cubed = 0.027
The number is -6
A number can't be cubed and prime. Cubed numbers (other than 1) have more than two factors.
It is about 6.055048947
The third cubed number is (3^3), which equals (27). Cubed numbers are obtained by raising a number to the power of three, so the first few cubed numbers are (1^3 = 1), (2^3 = 8), and (3^3 = 27). Thus, the third cubed number is 27.
5.7689982812296335292865532431204 cubed = 192
0.3 cubed = 0.027
The cubed root of 343 is 7
The number 12.
The number is -6
A number can't be cubed and prime. Cubed numbers (other than 1) have more than two factors.
Just try cubing some small numbers. You should find the solution quickly.
17.890001
10 does.
It is about 6.055048947
6.2402514691557123435901704730737