First of all, the question does not require the numbers to be integers. That being the case, there are an infinite number of solutions. One of them being:
So 23 + 33 = (3√35)3
So, 2, 3 and the cibe root of 35 meet the requirements.
If they do need to be integers, then (-1)3 + (1)3 = 03 is a possible solution.
Finally if x, y and z need to be positive integers then
xn + yn = zn does not have a solution for n>2 according to Fermat's last theorem.
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0.3 cubed = 0.027
The number is -6
A number can't be cubed and prime. Cubed numbers (other than 1) have more than two factors.
It is about 6.055048947
6.2402514691557123435901704730737