As a product of its prime factors: 2*3*3*3 = 54
The cube root of 54 isn't an integer. 2 x 2 = 4, the cube root of 64.
2 and 135, 27 and 10, 54 and 5, 9 and 30, 3 and 90
There are none because when the given numbers are converted into a quadratic equation its discriminant is less than zero and so therefore there are no solutions. If the 2 numbers when multiplied equals -45 then the number are:- (3+square root of 54) and (3-square root of 54) Check: (3+sq rt 54)+(3-sq rt 54) = 6 Check: (3+sq rt 54)*(3-sq rt 54) = -45
54
As a product of its prime factors: 2*3*3*3 = 54
In order to find common factors you need two or more numbers. However, the factors of 54 (at least 2 numbers that can be multiplied evenly, or with no remainder, into 54) are: 1,2,3,6,9,18,27, and 54.
9*6 = 54
9 multiplied by 6 equals 54. 2 times by 27 equals 54
6 x 9 = 54 Hope these helps (:
108
The cube root of 54 isn't an integer. 2 x 2 = 4, the cube root of 64.
2 and 135, 27 and 10, 54 and 5, 9 and 30, 3 and 90
27*2 = 54
There are none because when the given numbers are converted into a quadratic equation its discriminant is less than zero and so therefore there are no solutions. If the 2 numbers when multiplied equals -45 then the number are:- (3+square root of 54) and (3-square root of 54) Check: (3+sq rt 54)+(3-sq rt 54) = 6 Check: (3+sq rt 54)*(3-sq rt 54) = -45
There are infinitely many possible answer. 1, 2 and 27 or 2, 4 and 6.75 are two triplets.
2 x 27 3 x 18 6 x 9