1 x 54, 2 x 27, 3 x 18, 6 x 9
As a product of its prime factors: 2*3*3*3 = 54
The cube root of 54 isn't an integer. 2 x 2 = 4, the cube root of 64.
2 and 135, 27 and 10, 54 and 5, 9 and 30, 3 and 90
The factors of 54 are the numbers that can be multiplied together to yield 54. These factors are 1, 2, 3, 6, 9, 18, 27, and 54. In pairs, they can be grouped as (1, 54), (2, 27), (3, 18), and (6, 9).
There are none because when the given numbers are converted into a quadratic equation its discriminant is less than zero and so therefore there are no solutions. If the 2 numbers when multiplied equals -45 then the number are:- (3+square root of 54) and (3-square root of 54) Check: (3+sq rt 54)+(3-sq rt 54) = 6 Check: (3+sq rt 54)*(3-sq rt 54) = -45
As a product of its prime factors: 2*3*3*3 = 54
In order to find common factors you need two or more numbers. However, the factors of 54 (at least 2 numbers that can be multiplied evenly, or with no remainder, into 54) are: 1,2,3,6,9,18,27, and 54.
9*6 = 54
9 multiplied by 6 equals 54. 2 times by 27 equals 54
6 x 9 = 54 Hope these helps (:
The cube root of 54 isn't an integer. 2 x 2 = 4, the cube root of 64.
2 and 135, 27 and 10, 54 and 5, 9 and 30, 3 and 90
27*2 = 54
There are none because when the given numbers are converted into a quadratic equation its discriminant is less than zero and so therefore there are no solutions. If the 2 numbers when multiplied equals -45 then the number are:- (3+square root of 54) and (3-square root of 54) Check: (3+sq rt 54)+(3-sq rt 54) = 6 Check: (3+sq rt 54)*(3-sq rt 54) = -45
There are infinitely many possible answer. 1, 2 and 27 or 2, 4 and 6.75 are two triplets.
2 x 27 3 x 18 6 x 9
(54,1)(27,2)(18,3)(9,6)