1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.
1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63 and 126.
The greatest common factor of the numbers 126 and 8 is 2.
Try: 2*9*7 = 126
First 125 numbers sum to 125/2 x 126, so first 125 even numbers sum to double that ie 125 x 126 = 15750
Yes, these numbers go into 126 evenly: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.
1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126
252
1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.
1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63 and 126.
The prime factors of 126 are 2, 3 and 7
126 = 1 x 126, 2 x 63, 3 x 42, 6 x 21, 7 x 18, 9 x 14.
63 can go into 126 exactly 2 times, since 63 x 2 = 126.
:D The factors of 126 is 1, 2, 3, 6, 9, 14, 21, 42, 63, and 126 :D And dont be a lazy poo :-{0 <3
First 125 numbers sum to 125/2 x 126, so first 125 even numbers sum to double that ie 125 x 126 = 15750
Any element of the set of numbers of the form 126*k, where k is an integer, is evenly divisible.
The prime factors of 126 are 2 x 3 x 3 x 7.