100 + 49 + 1
2 and 1 .their sum is 3 .difference is 1
55
The numbers are 15 and 1
24 and 25. To solve almost any question like this mathematically by using simple algebra. For example: Let one of the numbers be x and the other be x + 1. Then x + x + 1 = 49 so 2x + 1 = 49 so 2x = 48 so x = 24 and the other is x + 1 = 25.
1 + 3 + 5 + ... + 49 = ((49 + 1)/2)2 = 625
81 + 1 + 1 + 1
100 + 49 + 1
2 and 1 .their sum is 3 .difference is 1
1 and 0 are the two whole numbers with their sum same as their difference
55
The numbers are 15 and 1
24 and 25. To solve almost any question like this mathematically by using simple algebra. For example: Let one of the numbers be x and the other be x + 1. Then x + x + 1 = 49 so 2x + 1 = 49 so 2x = 48 so x = 24 and the other is x + 1 = 25.
15 + 1 = 16 sum 15 - 1 = 14 difference
1
10
8