The numbers 40.5 and 36.5 have a difference of 4 and a sum of 77.
It is: (77+32)*(56-45) = 1199
11 and 66.
65 and 77
If: 3x+2x = 77 Then: 5x = 77 => x = 15.4 The numbers which are not integers are: 46.2+30.8 = 77
Let's denote the two numbers as x and y. Since their sum is 77, we can write the equation x + y = 77. Given that their difference is 29, we have the equation x - y = 29. By solving these two equations simultaneously, we find that the two numbers are 53 and 24.
The numbers 40.5 and 36.5 have a difference of 4 and a sum of 77.
the sum of two whole numbers are 77 .their difference is 48.what are the two numbers
Do-it-in-your-head method: 77 minus 29 is 48, half of 48 is 24, 24 add 29 is 53 so your numbers are 24 and 53. Shazam!
a + b = 77a - b = 1Add the two equations: 2a = 78, a = 39, so 39 - b = 1 : b = 38.Check answer in first eq: 39 + 38 = 77
The difference between 400 and the sum of 821 and 77 can be calculated by first finding the sum of 821 and 77, which is 898. Then, subtract 898 from 400 to find the difference. Mathematically, this can be represented as 400 - (821 + 77) = 400 - 898 = -498. Therefore, the difference between 400 and the sum of 821 and 77 is -498.
The numbers are 38 and 39.
The sum of the first 8 prime numbers is 77.
The numbers are 76 and 77.
-73
It is: (77+32)*(56-45) = 1199
11 and 66.