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Let one of the numbers be x, then other number = 4-x

According to question:

Product of these two numbers = 45

i.e. x(4-x) = 45

4x - x2 = 45

Multiplying both sides by -1 we get

x2 - 4x = -45

x2 - 4x + 45 = 0

This equation is of the form: ax2 + bx +c = 0

Comparing both equations we get: a = 1, b = -4 and c = 45.

Using these values we will calculate D, D = b2- 4ac

Plugging in the values, we get D = 16 - 4(1)(45) = 16 - 180 = -164.

If the value of D is greater than or equal to zero, then real roots exist but here D<0 so, no real roots exist.

Value of x is calculated by using the relation:

x = (-b + D1/2)/2a or x = (-b - D1/2)/2a

If we put value of D here it is clear that square root of -164 doesn't exist. So, no real roots exist.

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Q: What 2 numbers when multiplied equal 45 and when added equals to 4?
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