Let one of the numbers be x, then other number = 4-x
According to question:
Product of these two numbers = 45
i.e. x(4-x) = 45
4x - x2 = 45
Multiplying both sides by -1 we get
x2 - 4x = -45
x2 - 4x + 45 = 0
This equation is of the form: ax2 + bx +c = 0
Comparing both equations we get: a = 1, b = -4 and c = 45.
Using these values we will calculate D, D = b2- 4ac
Plugging in the values, we get D = 16 - 4(1)(45) = 16 - 180 = -164.
If the value of D is greater than or equal to zero, then real roots exist but here D<0 so, no real roots exist.
Value of x is calculated by using the relation:
x = (-b + D1/2)/2a or x = (-b - D1/2)/2a
If we put value of D here it is clear that square root of -164 doesn't exist. So, no real roots exist.
000
The numbers are -10 and -70
99
-8 and -8
-3, -6
The numbers are 10 and 5.2
-2
-70
-9+4
8, 5 and 2
The numbers are: 30 and -30
2.4115 and 33.5885 (to 4 dp)
5
When added? multiplied?
The numbers are 1 and 10.
10
266