Let one of the numbers be x, then other number = 4-x
According to question:
Product of these two numbers = 45
i.e. x(4-x) = 45
4x - x2 = 45
Multiplying both sides by -1 we get
x2 - 4x = -45
x2 - 4x + 45 = 0
This equation is of the form: ax2 + bx +c = 0
Comparing both equations we get: a = 1, b = -4 and c = 45.
Using these values we will calculate D, D = b2- 4ac
Plugging in the values, we get D = 16 - 4(1)(45) = 16 - 180 = -164.
If the value of D is greater than or equal to zero, then real roots exist but here D<0 so, no real roots exist.
Value of x is calculated by using the relation:
x = (-b + D1/2)/2a or x = (-b - D1/2)/2a
If we put value of D here it is clear that square root of -164 doesn't exist. So, no real roots exist.
000
The numbers are -10 and -70
99
-8 and -8
-3, -6
The numbers are 10 and 5.2
-2
-70
-9+4
8, 5 and 2
The numbers are: 30 and -30
2.4115 and 33.5885 (to 4 dp)
5
The two numbers that equal 118 are 59 and 59. This is because when you add 59 and 59 together, you get 118. These two numbers are equal and satisfy the equation 59 + 59 = 118.
The numbers are 1 and 10.
10
266