How can 2 prime numbers ever be equal They cant be Equal.
2 + 3 + 1 = 6, which is divisible by 3, so 231 is divisible by 3. Divide to get 231 = 77 Hard to miss that this is divisible by 7, so we get 231 = 3*7*11
19 and 11 are the two prime numbers that equal to 209.
120 = 2*2*2*3*5, so there is 5 prime numbers, no 2 prime numbers
the prime numbers that equal 168 is 2*2*2*3*7 and also Here is a table of all prime numbers up to 1,000:2357111317192329313741434753596167717379838997101103107109113127131137139149151157163167173179181191193197199211223227229233239241251257263269271277281283293307311313317331337347349353359367373379383389397401409419421431433439443449457461463467479487491499503509521523541547557563569571577587593599601607613617619631641643647653659661673677683691701709719727733739743751757761769773787797809811821823827829839853857859863877881883887907911919929937941947953967971977983991997
They are: 2+229 = 231
How can 2 prime numbers ever be equal They cant be Equal.
2 + 3 + 1 = 6, which is divisible by 3, so 231 is divisible by 3. Divide to get 231 = 77 Hard to miss that this is divisible by 7, so we get 231 = 3*7*11
19 and 11 are the two prime numbers that equal to 209.
No, the product of two prime numbers is unique.
120 = 2*2*2*3*5, so there is 5 prime numbers, no 2 prime numbers
the prime numbers that equal 168 is 2*2*2*3*7 and also Here is a table of all prime numbers up to 1,000:2357111317192329313741434753596167717379838997101103107109113127131137139149151157163167173179181191193197199211223227229233239241251257263269271277281283293307311313317331337347349353359367373379383389397401409419421431433439443449457461463467479487491499503509521523541547557563569571577587593599601607613617619631641643647653659661673677683691701709719727733739743751757761769773787797809811821823827829839853857859863877881883887907911919929937941947953967971977983991997
No prime numbers equal 84. The only number equal to 84 is 84,and it isn't a prime number.The prime factors of 84 are: 1, 2, 2, 3, and 7
To determine factors of a number it is necessary to divide the number by prime numbers of increasing value. If there is no remainder then the prime number is a factor. The square root of 231 is approximately 15 so it is necessary to divide by all the prime numbers up to 13 (15 is not a prime number). 231 ÷ 2 leaves a remainder of 1 231 ÷ 3 divides exactly 77 times (which is 7 x 11 - both are prime numbers) 231 ÷ 5 leaves a remainder of 1 231 ÷ 7 divides exactly 33 times (which is 3 x 11 - both are prime numbers) 231 ÷ 11 divides exactly 21 times (which is 3 x 7 - both are prime numbers) 231 ÷ 13 leaves a remainder of 10 If we multiply together the three numbers that are shown to be factors 3 x 7 x 11 = 231 this confirms that there are no other factors of 231 except 1 and 231 itself. This last condition is true for every positive integer. 231 is divisible by 1, 3, 7, 11 and 231
The prime factorization of 58 is: 2 x 29, so 2 and 29 are the two prime numbers that equal 58.
The prime numbers (factors) of 108 are: 2 and 3
The prime numbers (factors) of 250 are: 2 and 5