32-22=5
9-4=5
9 and 1
-12
The two square numbers that, when one is subtracted from the other, equal seven are 16 and 9. This is because (4^2 - 3^2 = 16 - 9 = 7). Thus, the square numbers are 16 (from (4^2)) and 9 (from (3^2)).
Let the two square numbers be ( a^2 ) and ( b^2 ), where ( a^2 - b^2 = 21 ). This can be factored as ( (a-b)(a+b) = 21 ). The pairs of factors of 21 are (1, 21) and (3, 7). Solving these gives the pairs ( (11, 10) ) or ( (5, 4) ), leading to the square numbers ( 121 ) and ( 100 ) or ( 25 ) and ( 16 ). Thus, the two square numbers can be ( 121 ) and ( 100 ) or ( 25 ) and ( 16 ).
There is a difference of 95 when the prime number 2 is subtracted from the prime number 97.
2 square numbers subtracted from each other to make 8 = -6
9 and 1
-12
The two square numbers that, when one is subtracted from the other, equal seven are 16 and 9. This is because (4^2 - 3^2 = 16 - 9 = 7). Thus, the square numbers are 16 (from (4^2)) and 9 (from (3^2)).
Let the two square numbers be ( a^2 ) and ( b^2 ), where ( a^2 - b^2 = 21 ). This can be factored as ( (a-b)(a+b) = 21 ). The pairs of factors of 21 are (1, 21) and (3, 7). Solving these gives the pairs ( (11, 10) ) or ( (5, 4) ), leading to the square numbers ( 121 ) and ( 100 ) or ( 25 ) and ( 16 ). Thus, the two square numbers can be ( 121 ) and ( 100 ) or ( 25 ) and ( 16 ).
There is a difference of 95 when the prime number 2 is subtracted from the prime number 97.
No.
Added: 4.5 ± 12.6392 i where i is the imaginary square root of -1
The number is two
60
5
The two square numbers that satisfy the equation when one is subtracted from the other to give 7 are 9 and 2. Specifically, (9 - 2 = 7), where (9) is (3^2) and (2) is (1.414^2) when considering perfect squares. However, the perfect squares that work are (9) (from (3^2)) and (4) (from (2^2)), since (9 - 4 = 5). So, the two square numbers are (9) and (4).